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Using FCC GW graphs & M3 map, am I estimating field strengths correctly?

I'm attempting to use the M3 map and the FCC groundwave curves graphs to estimate field strengths of some stations, mostly at my location, but also at a few other places for a couple stations. I understand that the graphs are "calibrated" to 100 mV/m @ 1 km and I need to adjust based on the 1 km field of the station as specified in the FCC database. (For directional stations, I use the field in the direction I want to measure.) I'm wondering, though, if I'm doing the calculations correctly? I've noticed that not all the conductivity lines for all the frequencies are at the 100 mV/m level at 1 km. For example, on the graph for 1560 kHz, it shows a field of about 30.5 mV/m @ 1 km for a conductivity of 0.1 mS/m. I've been assuming I need to base my initial conversion factor on the 100 mV/m level, regardless of the actual ground conductivity.

Here's an example of how I'm doing the calculations. I've patched together the western portion of the large M3 map in GIMP, but there are some imperfect seams. I've already figured out my location (and drawn a crosshair on the map). I have two ways of estimating the transmitter site. One is I take a screenshot of it on google maps, rotate and scale it (after measuring the length and angle of a straight state border), overlay it on the M3 map at half opacity, then draw a crosshair at the bottom of the marker. The other way is I measure the state lines, calculate a scale conversion factor, measure from a tri-corner border or the coast, then up at a 90° angle to the transmitter site and place the crosshair. I then draw a straight line on the M3 map from the transmitter's crosshair to my location, then measure the path length, from the transmitter site, to the various changes in conductivity. With the help of the FCC search, I calculate the actual length (in km) of the paths.

As an example, I'll use a fictitious station on 1560 kHz with a specified field at 1 km of 1,000 mV/m. Since 1000 (actual field) / 100 (graph calibration) = 10, that's my initial conversion factor. For the first 20 km, the conductivity is 0.1 mS/m. At that point, the graph says 0.12 mV/m. Multiplying that by the initial conversion factor gives me a reading of 1.2 mV/m.
The next 80 km (to 100 km) is saltwater, with a conductivity of 5000 mS/m, which reads about 4.94 mV/m at 20 km on that graph. Dividing 1.2 (actual field) by 4.94 (what graph says) gets me 0.2429, my new conversion factor. At 100 km (20 + 80) the 5,000 mS/m graph says 0.86 mV/m. Multiply that by the conversion factor (0.243) gets me a field of about 0.2089 mV/m.
For the next (and final) 60km, the conductivity is 8 mS/m. At 100km for 8 mS/m, the graph says 0.026 mV/m. Again, dividing 0.2089 (actual field) by 0.026 (graph) gets me 8.03488, the final conversion factor. At 160 km, the 8 mS/m graph says 0.0076 mV/m. Multiply that by the conversion factor (8.03488) results in a calculated field of 0.061 mV/m @ 160 km, a signal that based on my previous experiences & calculations should be listenable (if somewhat weak) on a portable radio in a quiet environment.

Am I doing these calculations correctly, or do I need to make any modifications to my methods (including any that will streamline the process, short of spending any $ on a FIM)? Also, how do I make calculations when I'm "falling off the bottom edge of the graph" before I reach the end of that measurement segment, even though I'm still able to hear the signal in some cases? For example, this happened when attempting to calculate the field at my location for 700 KALL North Salt Lake City, a signal I've heard near noon with the PL-606 and Select-A-Tenna on several occasions here near El Cajon / La Mesa, CA. Also at approximately what distance do I switch between calculating based on the actual ground conductivity vs. the inverse distance formula, and/or calculate based on the non-directional RMS field of a directional station when I'm estimating the field fairly close to the transmitter site (for example, within a few km, or within a few wavelengths, or in a few cases between towers - closer to one than to another)?
 
tfcwings said:
... I've noticed that not all the conductivity lines for all the frequencies are at the 100 mV/m level at 1 km. For example, on the graph for 1560 kHz, it shows a field of about 30.5 mV/m @ 1 km for a conductivity of 0.1 mS/m.

The only field that will be exactly 100 mV/m at a distance of 1 km for every frequency is the inverse distance field -- which is exactly that on the FCC chart for 1560 kHz. Groundwave propagation loss on 1560 kHz for 0.1 mS/m conductivity reduces that 100 mV/m value to about 30 mV/m even over the short path length of 1 km.

It is the function of the charts to show how various conductivities reduce the inverse distance value for various path lengths.

For example, here is the approach to find the groundwave field at 10 km over a 15 mS/m path from a 5 kW non-D AM on 930 kHz, having a theoretical field of 306 mV/m at 1 km for 1 kW of applied power.

1. Find the theoretical field for 5 kW, which is SQRT(5) * 306 = 684 mV/m.

2. Using the FCC chart for 920-950 kHz, find that the curve for 15 mS/m conductivity crosses the 10 km line at a field value of about 8.4 mV/m.

The field for our example then will be 6.84 * 8.4 = 57.5 mV/m, because the chart is based on 100 mV/m IDF at 1 km, and we have 6.84 X that value at that distance (all numbers are approximate).

The charts also may be used with an accurately measured field intensity value to find the effective conductivity producing that field value at that distance.

Calculating groundwave loss over a path having several values of conductivity along its length is not so straightforward. Suggest you research on the web for "FCC equivalent distance method."

Or in many cases you can save your effort, and look up the field to be expected for a given station in a given ZIP code using the V-Soft website.

... calculate based on the non-directional RMS field of a directional station when I'm estimating the field fairly close to the transmitter site (for example, within a few km, or within a few wavelengths, or in a few cases between towers - closer to one than to another)?

Calculating fields using the FCC groundwave charts close to or within the tower set used in a directional AM array is impossible. Those charts do not apply for distances from the radiation center of the array less than about 10 X the greatest physical separation of the installed towers.
 
Ok, so I looked up FCC equivalent distance method and came up with a link to 73.183 in the FCC rules.
It is desired to determine the distance to the 0.5 mV/m and 0.025 mV/m contours of a station on a frequency of 1000 kHz with an inverse distance field of 100 mV/m at one kilometer being radiated over a path having a conductivity of 10 mS/m for a distance of 20 kilometers, 5 mS/m for the next 30 kilometers and 15 mS/m thereafter. Using the appropriate curve in § 73.184, Graph 12, at a distance of 20 kilometers on the curve for 10 mS/m, the field strength is found to be 2.84 mV/m. On the 5mS/m curve, the equivalent distance to this field strength is 14.92 kilometers, which is 5.08 (20¥14.92 kilometers nearer to the transmitter. Continuing on the propagation curve, the distance to a field strength of 0.5 mV/m is found to be 36.11 kilometers.
The actual length of the path travelled, however, is 41.19 (36.11+5.08) kilometers. Continuing on this propagation curve to the conductivity change at 44.92 (50.00¥5.08) kilometers, the field strength is found to be 0.304 mV/m. On the 15 mS/m propagation curve, the equivalent distance to this field strength is 82.94 kilometers, which changes the effective path length by 38.02 (82.94¥44.92) kilometers. Continuing on this propagation curve, the distance to a field strength of 0.025 mV/m is seen to be 224.4 kilometers. The actual length of the path travelled, however, is 191.46 (224.4+5.08¥38.02) kilometers.

Now I want to find out if I understand it correctly...

One station I want to calculate is 960 KIXW Apple Valley, CA, which is 196.95 km from me at a heading (from the station to me) of 172.34°. The station is 5kW omnidirectional with an efficiency of 308.99 mV/m @ 1 km for 1 kW, which translates to {308.99*sqrt(5)} about 690.92 mV/m @ 1 km. The path has a conductivity of 8 mS/m for the first 14.9 km, 4 mS/m to 96.95 km, and 8 mS/m for the rest of the path.
Tracing the 8 mS/m curve on the 940 kHz graph to 14.9 km reveals a field strength of 4.1 mV/m. On the 4 mS/m graph, this field is found at a distance of 11.3 km, reducing the effective path length by {14.9-11.3} 3.6 km.
Next, tracing the 4 mS/m curve to {96.95-3.6} 93.36 km gives a field of 0.0468 mV/m. On the 8 mS/m curve, the distance to that field is about 133.5 km. This increases the effective path length by {133.5-93.36} 40.14 km. Now, in order to find the field at 196.95 km, due to the different conductivities changing the path length I need to find the field at {0-40.14+3.6-196.95=-233.49} 233.49 km.
On the 8 mS/m curve, the field at 233.49 km is found to be 0.008 mV/m. Because the graphs are based on 100 mV/m at 1 km and the station has a field of 690.92 mV/m, the actual field is found to be {0.008 * 6.9092} = 0.0552736 mV/m, or 55.2736 µV/m. BTW according to Radio-Locator's coverage map, I'm about 33% outside the 0.15 mV/m contour for the station. However, I can hear their signal, if a bit weak.

Another station I've heard at around midday is 700 KALL North Salt Lake City, UT, at a distance of 1007.25 km and a heading (from the station to me) of 207.76°. The estimated field at 1 km, based on looking at the pattern plot, is about 4,400 mV/m in my direction. The path has a conductivity of 15 mS/m to 626.9 km, 8 mS/m to 848.15 km, 2 mS/m to 901.68 km, 4 mS/m to 971.7 km, and 8 mS/m to my location at 1007.25 km.
Tracing the 15 mS/m curve to 626.9 km on the 700 kHz graph puts the field at approximately 0.00166 mV/m. On the 8 mS/m graph, the distance to that field is found to be about 493 km, decreasing the effective path length by {626.9-493} 133.9 km. With the change in path length, the next conductivity change is at {848.15-133.9} 714.25 km. Tracing the 8 mS/m graph to that distance reveals a field of about 0.000233 mV/m. On the 2 mS/m curve, this field is found at a distance of about 508 km, reducing the path length by another {714.25-508} 206.25 km.
Next, tracing the 2 mS/m curve to {901.68-206.25-133.9} 561.53 km gives a field of about 0.00033 mV/m. On the 4 mS/m curve, the distance to this field is found at approximately 653 km, increasing the path length by {653-561.53} 91.47 km.
Next, in order to find the next conductivity change at 971.7 km, I need to go to {971.7-133.9-206.25+91.47} 723.02 km on the graph. However, the 4 mS/m graph bottoms out at 0.0001 mV/m @ 685 km, or an actual distance of {685+133.9+206.25-91.47} 933.68 km. Taking into account the station's field in my direction, that field strength is found to be 0.0044 mV/m, or 4.4 µV/m. However, the signal still has another {1007.25-933.68} 73.57 km to traverse, as well as a conductivity change to 8 mS/m at 971.7 km. What do I do in this case?
I also ran into the same problem when attempting to calculate the field of 1100 KFNX Cave Creek, AZ, at my friends' house about 1 km west of the array for 1110 KDIS Pasadena, CA. (If KDIS shut off the IBOC and turned the C-Quam back on while opening the analog bandwidth back to what it used to be (NRSC mask, IIRC), would there be a way to get KFNX's signal in the daytime at my friends' house with better-than-analog-on-IBOC audio quality / frequency response, if I've been able to hear similar-field-strength signals at other locations around midday? There is also a 50kW station on 1090 in Baja whose directional antenna puts a good signal into the L.A. area so that would need to be taken into account as well.)



Also, since the graphs don't apply within 10x the greatest physical separation of the towers, how would I find the field strengths of, for example:

590 KTIE at 2.01 meters from the closest leg of the center tower, or 6.32 meters from the farthest leg of the same tower (with the center being approximately 4.15 meters away). (The fence is 1.5 meters away from the nearest leg of the self-supporting tower to where I was at the time.)

910 KECR at 32°53'37.8126"N 116°55'40.3896"W, or approximately 176 meters from the nearest tower used in the daytime pattern. (They use the two towers at the north end of the array, the 2nd of the 4 in line (counting from west), and the odd-tower-out just s/se of the 4-in-line.)

1170 KCBQ at 32°53'37.8126"N 116°55'40.3896"W, or approximately 92.7 meters from the nearest tower used for their daytime pattern. (They use the 4-in-line for their day pattern.)

1290 KKDD at 34°7'26.7522"N 117°14'20.0286"W, or approximately 26.64 meters from the southwest tower.

1300 KAZN and 1430 KMRB at approximately 600 meters SE of the array (separation between the farthest towers in the array is approximately 150 meters).

1450 KFSD at 33°7'2.8344"N 117°7'12.5214"W, or approximately 20.69 meters from the nearest leg of the self-supporting tower

Since the groundwave charts don't apply within 10x the greatest physical separation between towers, is there another way to calculate those near ones? For example, would I calculate based on the inverse distance method based on the RMS, or based on the field in my direction?
 
tfcwings said:
Ok, so I looked up FCC equivalent distance method and came up with a link to 73.183 in the FCC rules.... Now I want to find out if I understand it correctly...

The correct answer to this question lies in the correct understanding and application of the information given in the FCC reference.

Since the groundwave charts don't apply within 10x the greatest physical separation between towers, is there another way to calculate those near ones?

No. The electric (and magnetic) fields close to a single radiating source are much higher, and decay much faster than those further away.

Adding more radiating sources nearby such as those in a directional array only complicate this reality.
 
Me thinks this exercise is tantamount fishing for great white whales with a harmonica...

Best regards,
w/
 
Watt, I agree. Makes a difference if you hold the harmonica right side up, or up side down.

Either way, without field strength data from the station you're trying to predict, you are wasting your time.
 
I am getting field strength data.. from the "mV/m @ 1 km" info in the FCC database. Then, I'm using the FCC groundwave curves graphs and the larger version of the M3 map (stitched together) to calculate an approximate field strength at my location, hopefully with an accuracy within a dB or two. I'm still having a few hangups, though. For one thing, I'm not sure I'm calculating correctly across changes in ground conductivity. Also, there have been several cases in which my "trace" fell off the bottom of the graph, yet I was still able to hear the station in bright daylight from considerably farther. Also, Rich is saying that the groundwave graphs don't apply within 10x the spacing of the farthest-separated towers in a DA, and there's at least one case I want to calculate where I was about 1/3 the distance from one leg of a self-supporting tower vs. a leg on the other side of the tower. (No, I wasn't literally UNDER it, although my neck almost hurt looking for the top of it (590 kHz), and I was outside the fence surrounding the tower.) I've thought about using inverse distance based on the mV/m @ 1 km, but 1 - I get the impression based on other posts that doesn't apply, and 2 - I'm not sure what field I'd base my calculation on when I'm standing that close to one tower in a DA.
 

  • Key points here:
    • The radiation patterns and relative fields shown in the FCC online data for directional AM broadcast stations do not apply closer than about 10X the greatest physical separation of the towers in the array because it takes that amount of h-plane distance from the center of the array for the net radiation pattern to take its final form.
    • Field intensities measured in the "near field" of a radiating source or combination of radiating sources do not follow either the inverse distance value or the FCC MW propagation charts. The near field of each single radiator exists to radius distance of about 2*L2/ lambda, where L = radiator length (height) and lambda is the wavelength.
    • The above realities apply to measurements made by professional engineers using accurately-calibrated field intensity test equipment, as well as to everyone else. This certainly applies to a 1/3 - 2/3 distance split between the legs of a self-supporting tower.
 
R. Fry said:

  • Key points here:
    • The radiation patterns and relative fields shown in the FCC online data for directional AM broadcast stations do not apply closer than about 10X the greatest physical separation of the towers in the array because it takes that amount of h-plane distance from the center of the array for the net radiation pattern to take its final form.
    • Field intensities measured in the "near field" of a radiating source or combination of radiating sources do not follow either the inverse distance value or the FCC MW propagation charts. The near field of each single radiator exists to radius distance of about 2*L2/ lambda, where L = radiator length (height) and lambda is the wavelength.
    • The above realities apply to measurements made by professional engineers using accurately-calibrated field intensity test equipment, as well as to everyone else. This certainly applies to a 1/3 - 2/3 distance split between the legs of a self-supporting tower.


  • I don't remember you specifying it in the equation, but I'm assuming that "L" and "λ" are in meters, right? The wavelength of KTIE is 508.12281 meters, and the 65.2° tower is 92.0267 meters tall. (The field ratio for tower #2, the one I was near, is 1.162, and the phasing is -138.7°, in case that would help me with calculations.) Therefore it seems to me that the near field for that tower exists out to ... 33.334 meters from the tower? That doesn't seem right. I thought the near field was out to several wavelengths, unless I did the calculation wrong? 2*((92.0266861167)^2)/508.122806779661
    Once I properly figure out the rule for determining where near field is, then how is field strength calculated/estimated within that near field - what's the rule (since it's not inverse distance nor using the groundwave graphs)?
 
tfcwings said:
Once I properly figure out the rule for determining where near field is, then how is field strength calculated/estimated within that near field - what's the rule (since it's not inverse distance nor using the groundwave graphs)?

There is relatively little interest in this subject as normally no one is attempting to listen to a radio station at such extremely close locations to (or within) its antenna system.

The electric and magnetic fields close to one of the towers of a directional array are functions of the base currents, feedpoint impedances, excitation phases, geometric relationship of all of the towers in the array, and the physical location where the fields exist.

Calculating such fields rarely is done, but if you wish to pursue this you might want to read the paper linked below, especially pages 5-6.

Also the study of the appropriate chapters in an antenna engineering textbook such as Antennas for All Applications, 3rd edition, by John Kraus (McGraw Hill) will give you some background on this subject -- which is more complex than can be presented here.

http://www.hatdaw.com/papers/nearly_seven_years_of_success.PDF
 
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